9a^2+15a-50=0

Solution for 9a^2+15a-50=0 equation:

9a^2+15a-50=0

a = 9; b = 15; c = -50;
Δ = b2-4ac
Δ = 152-4·9·(-50)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-45}{2*9}=\frac{-60}{18}
=-3+1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+45}{2*9}=\frac{30}{18}
=1+2/3
$